Question

mn ơi giúp mình vs:

Answer 1

\(=\dfrac{5\cdot2^{30}\cdot3^{18}-3^{20}\cdot2^{29}}{5\cdot2^{29}\cdot3^{32}-7\cdot2^{29}\cdot3^{18}}\)

\(=\dfrac{2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)}{2^{29}\cdot3^{18}\left(5\cdot3^{14}-7\right)}=\dfrac{1}{5\cdot3^{14}-7}\)