a: \(=\dfrac{x-8}{\left(x-2\right)\left(x+2\right)}+\dfrac{3}{2\left(x-2\right)}\)\(=\dfrac{2x-16+3x+6}{\left(x-2\right)\left(x+2\right)\cdot2}=\dfrac{5}{2\left(x+2\right)}\)Câu trả lời: a: \(=\dfrac{x-8}{\left(x-2\right)\left(x+2\right)}+\dfrac{3}{2\left(x-2\right)}\)\(=\dfrac{2x-16+3x+6}{\left(x-2\right)\left(x+2\right)\cdot2}=\dfrac{5}{2\left(x+2\right)}\)