a, x=132
b,x=10
bài 2:
a, 22/55+25/125+1020/5100
=2/5+1/5+1/5=4/5
b, 22/77+56/98+25/105
=2/7+4/7+5/21
=6/21+12/21+5/21=23/21
a: Ta có: \(\dfrac{x}{33}=4\)
nên x=132
b: Ta có: \(\dfrac{5}{x}=\dfrac{1}{2}\)
nên x=10
a) \(\dfrac{x}{33}=4\Rightarrow x=33.4=132\)
b) \(\dfrac{5}{x}=\dfrac{1}{2}\Rightarrow x=5.2=10\)
a) \(\dfrac{22}{55}+\dfrac{25}{125}+\dfrac{1020}{5100}=\dfrac{2}{5}+\dfrac{1}{5}+\dfrac{1}{5}=\dfrac{4}{5}\)
b) \(\dfrac{22}{77}+\dfrac{56}{98}+\dfrac{25}{105}=\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{5}{21}=\dfrac{6+12+5}{21}=\dfrac{23}{21}\)
\(\dfrac{22}{55}+\dfrac{25}{125}+\dfrac{1020}{5100}=\dfrac{2}{5}+\dfrac{1}{5}+\dfrac{1}{5}=\dfrac{4}{5}\)
\(\dfrac{22}{77}+\dfrac{56}{98}+\dfrac{25}{105}=\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{5}{21}=\dfrac{23}{21}\)