Question

\(\left(\frac{-7}{8}x+\frac{6}{5}\right):\frac{15}{17}=\frac{34}{3}\)

Answer 1

\(\left(\dfrac{-7}{8}x+\dfrac{6}{5}\right):\dfrac{15}{17}=\dfrac{34}{3}\\ -\dfrac{7}{8}x+\dfrac{6}{5}=\dfrac{34}{3}\cdot\dfrac{15}{17}\\ -\dfrac{7}{8}x+\dfrac{6}{5}=10\\ \dfrac{7}{8}x=\dfrac{6}{5}-10\\ \dfrac{7}{8}x=-\dfrac{44}{5}\\ x=-\dfrac{44}{5}:\dfrac{7}{8}\\ x=-\dfrac{352}{35}\)