Question

\(\left(\dfrac{1}{3}\right)^2-\left(\dfrac{1}{9}-\dfrac{2023}{2024}\right)\)

Answer 1

\(\left(\dfrac{1}{3}\right)^2-\left(\dfrac{1}{9}-\dfrac{2023}{2024}\right)\)

\(=\dfrac{1}{9}-\dfrac{1}{9}+\dfrac{2023}{2024}\)

\(=\dfrac{2023}{2024}\)