\(\left(1-x\right)^2=2003.\left(x-1\right)\)
\(\left(1-x\right)^2-2003\left(x-1\right)=0\)
\(\left(1-x\right)^2+2003\left(1-x\right)=0\)
\(\left(1-x\right)\left(1-x+2003\right)=0\)
\(\left(1-x\right)\left(2004-x\right)=0\)
\(TH1:1-x=0\)
\(x=1\)
\(TH2:2004-x=0\)
\(x=2004\)
vậy........