Question

Làm hộ em phần b câu 2 và câu 3 ạ

Answer 1

2b)

xét vế trái ta có

=\(\left(\sqrt{x}-\sqrt{y}\right).\dfrac{\sqrt{x^2y}+\sqrt{xy^2}}{\sqrt{xy}}\) \(\left(\sqrt{x}-\sqrt{y}\right).\dfrac{\sqrt{xy}\left(\sqrt{x}+\sqrt{y}\right)}{\sqrt{xy}}\)=x-y

3b)

để A<0 \(\Rightarrow\dfrac{\sqrt{x}-1}{\sqrt{x}}< 0\)

\(\Rightarrow\sqrt{x}-1< 0\)\(\Rightarrow\sqrt{x}< 1\)\(\Rightarrow x< 1\)

Answer 2

a: Ta có: \(\sqrt{9x^2-6x+1}=5\)

\(\Leftrightarrow\left|3x-1\right|=5\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-1=5\\3x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=6\\3x=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-\dfrac{4}{3}\end{matrix}\right.\)