Question

Làm giúp mình với!

Answer 1

\(=\dfrac{x^2-x+4-3x}{x-2}=\dfrac{\left(x-2\right)^2}{x-2}=x-2\)

Answer 2

Answer 3

\(\dfrac{x^2-x}{x-2}+\dfrac{4-3x}{x-2}=\dfrac{x^2-x+4-3x}{x-2}=\dfrac{x^2-4x+4}{x-2}=\dfrac{\left(x-2\right)^2}{x-2}=x-2\)