2:
a: \(A\left(x\right)+B\left(x\right)\)
\(=3x^4-2x^3+x^2+x-2-2x^4+3x^2-2x+7\)
\(=x^4-2x^3+4x^2-x+5\)
Bậc là 4
b: A(x)-B(x)
\(=3x^4-2x^3+x^2+x-2+2x^4-3x^2+2x-7\)
\(=5x^4-2x^3-2x^2+3x-9\)
Bậc là 4
1:
a: \(=5x^6-2x^6+x^5-x^4+4x^3-x^3+3x^2-x\)
\(=3x^6+x^5-x^4+3x^3+3x^2-x\)
Bậc là 6
b: \(=7x^5-\dfrac{1}{2}x^5+4x^4-\dfrac{2}{3}x^4-5x^2-x^2+1\)
\(=\dfrac{13}{2}x^5+\dfrac{10}{3}x^4-6x^2+1\)
Bậc là 5
c: \(=6x^6-x^6-5x^6+3x^5+2x^5+x^4+3x^3-3x\)
\(=5x^5+x^4+3x^3-3x\)
Bậc là 5
d: \(=\dfrac{1}{5}x^3-\dfrac{3}{5}x^3+\dfrac{2}{3}x^2-\dfrac{7}{3}x^2+\dfrac{5}{3}x-x-2\)
\(=-\dfrac{2}{5}x^3-\dfrac{5}{3}x^2+\dfrac{2}{3}x-2\)
Bậc là 3
e: \(=\dfrac{13}{11}x^4+\dfrac{9}{11}x^4+\dfrac{11}{12}x^3-\dfrac{5}{12}x^3+3x^2-\dfrac{2}{9}x\)
\(=2x^4+x^3+3x^2-\dfrac{2}{9}x\)
Bậc là 4
