Question

help me: \(\left(6.\left(-\frac{1}{3}\right)^2-3.\left(-\frac{1}{3}\right)+1\right):\left(-\frac{1}{3}-1\right)\)

Answer 1

\(\left[6.\left(-\frac{1}{3}\right)^2-3.\left(-\frac{1}{3}\right)+1\right]:\left(-\frac{1}{3}-1\right)\)

\(=\left[6.\frac{1}{9}-\left(-1\right)+1\right]:\left(-\frac{4}{3}\right)\)

\(=\left[\frac{2}{3}+1+1\right]:\left(-\frac{4}{3}\right)\)

\(=\frac{8}{3}.\frac{-3}{4}\)

\(=-2\)

Answer 2

   help me       T×m mét sè cã ba ch÷ sè, biÕt  r»ng sè ®ã chia hÕt cho 18 vµ c¸c ch÷ sè cña nã tØ lÖ víi ba sè 1, 2 vµ 3.

Answer 3

-_-