Question

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Answer 1

a: \(-3x^2-8x+3=0\)

\(\Leftrightarrow3x^2+8x-3=0\)

\(\Leftrightarrow3x^2+9x-x-3=0\)

=>(x+3)(3x-1)=0

=>x=1/3 hoặc x=-3

b: \(\left\{{}\begin{matrix}2x+3y=4\\x+y=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x+3y=4\\2x+2y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=-6\\x=11\end{matrix}\right.\)