=>4(5x+3)-120=5(4x-21)
=>20x+12-120=20x-105
=>-108=-105(loại)
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Lời giải:
$\frac{5x+3}{15}-2=\frac{4x-21}{12}$
$\frac{5x}{15}+\frac{3}{15}-2=\frac{4x}{12}-\frac{21}{12}$
$\frac{x}{3}+\frac{1}{5}-2=\frac{x}{3}-\frac{7}{4}$
$\frac{x}{3}-\frac{9}{5}=\frac{x}{3}-\frac{7}{4}$
$\Rightarrow \frac{9}{5}=\frac{7}{4}$ (vô lý)
Vậy pt vô nghiệm.
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\(\dfrac{5x+3}{15}-2=\dfrac{4x-21}{12}\)
<=> \(\dfrac{4\left(5x+3\right)}{60}-2=\dfrac{5\left(4x-21\right)}{12}\)
<=> \(\dfrac{20x+12}{60}-2=\dfrac{20x-105}{60}\)
<=> \(\dfrac{20x+12}{60}=\dfrac{20x-105}{60}+2\)
<=> \(\dfrac{20x+12}{60}=\dfrac{20x-105+120}{60}\)
<=> \(\dfrac{20x+12}{60}=\dfrac{20x+15}{60}\) (không thỏa mãn)
=> \(\dfrac{5x+3}{15}-2\text{≠}\dfrac{4x-21}{12}\)
#Hy
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