Bài 22:
a: =>(x-3)(2x+5)=0
=>x=3 hoặc x=-5/2
b: =>(x-2)(x+2+3-2x)=0
=>(x-2)(5-x)=0
=>x=2 hoặc x=5
c: =>x-1=0
hay x=1
d: =>(2x-7)(x-2)=0
=>x=7/2 hoặc x=2
e: =>(2x-5-x-2)(2x-5+x+2)=0
=>(x-7)(3x-3)=0
=>x=7 hoặc x=1
f: =>x(x-1)-3(x-1)=0
=>x=1 hoặc x=3
21.
a) (3x-2)(4x+5)=0
Th1: 3x-2=0 Th2: 4x+5=0
3x=2 4x=-5
x=\(\dfrac{-5}{4}\)
Vậy ...
b) (2,3x-6,9)(0,1x+2)=0
Th1: 2,3x-6,9=0 Th2: 0,1x+2=0
2,3x=6,9 0,1x=-2
x=3 x=-0,2
Vậy ...
c) (4x+2)(x2+1)=0
2(2x+1)(x2+1)=0
Th1: 2x+1=0 Th2: x2+1=0
2x=-1 x2=-1(vô lí)
x=-1/2 (loại)
Vậy ...
d) (2x+7)(x-5)(5x+1)=0
Th1: 2x+7=0 Th2: x-5=0 Th3: 5x+1=0
2x=-7 x=5 5x=-1
x=-7/2 x=-1/5
Vậy ...
22.
a) 2x(x-3)+5(x-3)=0
(2x+5)(x-3)=0
Th1: 2x+5=0 Th2: x-3=0
2x=-5 x=3
x=-5/2
Vậy ...
b) (x2-4)+(x-2)(3-2x)=0
(x-2)(x+2)+(x-2)(3-2x)=0
(x-2)(x+2+3-2x)=0
(x-2)(-x+5)=0
Th1: x-2=0 Th2: -x+5=0
x=2 -x=-5
x=5
Vậy ...
c) x3-3x2+3x-1=0
(x-1)3=0
x=1
Vậy ...
d) x(2x-7)-4x+14=0
x(2x-7)-2(2x-7)=0
(x-2)(2x-7)=0
Th1: x-2=0 Th2: 2x-7=0
x=2 2x=7
x=7/2
Vậy ...
e) (2x-5)2-(x+2)2=0
(2x-5+x+2)(2x-5-x-2)=0
(3x-3)(x-7)=0
3(x-1)(x-7)=0
Th1: x-1=0 Th2: x-7=0
x=1 x=7
Vậy ...
f) x2-x-(3x-3)=0
x(x-1)-3(x-1)=0
(x-3)(x-1)=0
Th1: x-3=0 Th2: x-1=0
x=3 x=1
Vậy ...