Question

giúp mình bài 6

Answer 1

Bài 6: 

a: \(=\dfrac{21}{7}\cdot\dfrac{5}{25}\cdot\dfrac{11}{9}=3\cdot\dfrac{1}{5}\cdot\dfrac{11}{9}=\dfrac{11}{3}\cdot\dfrac{1}{5}=\dfrac{11}{15}\)

b: \(=\dfrac{5}{23}\left(\dfrac{17}{26}+\dfrac{9}{26}\right)=\dfrac{5}{23}\)

c: \(=\dfrac{15-29}{145}\cdot\dfrac{29}{3}=\dfrac{-14}{3}\cdot\dfrac{1}{5}=\dfrac{-14}{15}\)