\(\dfrac{4}{7}+\dfrac{2}{9}+\dfrac{1}{4}+\dfrac{3}{7}+\dfrac{7}{9}+\dfrac{75}{100}\\ =\dfrac{4}{7}+\dfrac{2}{9}+\dfrac{1}{4}+\dfrac{3}{7}+\dfrac{7}{9}+\dfrac{3}{4}\\ =\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{2}{9}+\dfrac{7}{9}\right)+\left(\dfrac{1}{4}+\dfrac{3}{4}\right)\\ =\dfrac{7}{7}+\dfrac{9}{9}+\dfrac{4}{4}\\ =1+1+1\\ =3\)
Ta có: \(\dfrac{7}{11}=\dfrac{7\times3}{11\times3}=\dfrac{21}{33};\dfrac{8}{11}=\dfrac{8\times3}{11\times3}=\dfrac{24}{33}\)
2 phân số giữa là: \(\dfrac{22}{33};\dfrac{23}{33}\)
\(=\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{2}{9}+\dfrac{7}{9}\right)+\left(\dfrac{1}{4}+\dfrac{3}{4}\right)=1+1+1=3\)
(\(\dfrac{4}{7}\)+\(\dfrac{3}{7}\))+(\(\dfrac{2}{9}\)+\(\dfrac{7}{9}\))+(\(\dfrac{1}{4}\)+\(\dfrac{75}{100}\))
=1+1+1
=3
\(\dfrac{4}{7}+\dfrac{2}{9}+\dfrac{1}{4}+\dfrac{3}{7}+\dfrac{7}{9}+\dfrac{75}{100}=\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{2}{9}+\dfrac{7}{9}\right)+\dfrac{1}{4}+\dfrac{75}{100}\)
\(=1+1+\dfrac{1}{4}+\dfrac{75}{100}\)
= 2 + \(\dfrac{1}{4}+\dfrac{75}{100}\)
= \(\dfrac{9}{4}+\dfrac{75}{100}=\dfrac{225}{100}+\dfrac{75}{100}=\dfrac{300}{100}=3\)
bài 1 thì có thể lm dc và mn đã làm nhưng bài thứ hai ko đủ dữ kiện bạn ạ
bạn thông cảm bọn ko báo cáo chỉ theo dõi thôi
