e: \(=\left(\dfrac{a\sqrt{ab}}{b}+2\sqrt{ab}+\dfrac{b\sqrt{ab}}{b}\right)\cdot\sqrt{ab}\)\(=ab\left(\dfrac{a}{b}+2+\dfrac{b}{b}\right)=ab\cdot\dfrac{a+b+2b}{b}=a\left(a+3b\right)\)f: \(=\left(1+\sqrt{a}+a+\sqrt{a}\right)\left(1-\sqrt{a}+a-\sqrt{a}\right)\)\(=\left(1-\sqrt{a}\right)^2\cdot\left(1+\sqrt{a}\right)^2=\left(1-a\right)^2=a^2-2a+1\)Câu trả lời: e: \(=\left(\dfrac{a\sqrt{ab}}{b}+2\sqrt{ab}+\dfrac{b\sqrt{ab}}{b}\right)\cdot\sqrt{ab}\)\(=ab\left(\dfrac{a}{b}+2+\dfrac{b}{b}\right)=ab\cdot\dfrac{a+b+2b}{b}=a\left(a+3b\right)\)f: \(=\left(1+\sqrt{a}+a+\sqrt{a}\right)\left(1-\sqrt{a}+a-\sqrt{a}\right)\)\(=\left(1-\sqrt{a}\right)^2\cdot\left(1+\sqrt{a}\right)^2=\left(1-a\right)^2=a^2-2a+1\)