Question

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Answer 1

a, \(\dfrac{4x}{7}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{13}{15}\Rightarrow60x=91\Leftrightarrow x=\dfrac{91}{60}\)

b, \(\dfrac{4}{5}+\dfrac{5}{7x}=\dfrac{1}{6}\Rightarrow\dfrac{5}{7x}=-\dfrac{19}{30}\Rightarrow7x\left(-19\right)=150\Leftrightarrow x=\dfrac{150}{7\left(-19\right)}=-\dfrac{150}{133}\)

Answer 2

a: =>4/7x=1/5+2/3=3/15+10/15=13/15

hay x=91/60

b: =>5/7:x=1/6-4/5=-19/30

hay x=-150/133