Question

ฅ^•ﻌ•^ฅ giúp mik đy :33

Answer 1

mờ quá mk ko thấy j cả! :_( 

Answer 2

h) Ta có: \(\dfrac{x+2}{5}\ge0\)

nên \(x+2\ge0\)

hay \(x\ge-2\)

i) Ta có: \(\dfrac{x+2}{x-3}< 0\)

nên \(\left\{{}\begin{matrix}x+2>0\\x-3< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>-2\\x< 3\end{matrix}\right.\Leftrightarrow-2< x< 3\)