Question

Giúp mik bài 3.6 với ạ.Mik đg cần gấp

Answer 1

\(3,6\\ a,=\dfrac{13}{4}+\dfrac{21}{4}=\dfrac{17}{2}\\ b,=\dfrac{23}{3}-\dfrac{13}{3}\\ =\dfrac{10}{3}\\ c,=\dfrac{25}{3}-\dfrac{37}{9}\\ =\dfrac{25.3-37}{9}\\ =\dfrac{38}{9}\\ d,=\dfrac{77}{6}+\dfrac{13}{3}\\ =\dfrac{77+13.2}{6}\\ =\dfrac{103}{6}\\ e,=\dfrac{8}{7}.\dfrac{21}{4}\\ =6\\ g,=\dfrac{19}{6}:\dfrac{5}{2}\\ =\dfrac{19}{6}.\dfrac{2}{5}\\ =\dfrac{19}{15}\)

Answer 2

3.6:

a: \(=3+\dfrac{1}{4}+5+\dfrac{1}{4}=8+\dfrac{1}{2}=8.5\)

b: \(=7+\dfrac{2}{3}-4-\dfrac{1}{3}=3+\dfrac{1}{3}=\dfrac{10}{3}\)

c: \(=\dfrac{25}{3}-\dfrac{37}{9}=\dfrac{38}{9}\)

d: \(=12+\dfrac{5}{6}+4+\dfrac{1}{3}=16+\dfrac{7}{6}=\dfrac{103}{6}\)

e: \(=\dfrac{8}{7}\cdot\dfrac{21}{4}=6\)