Câu 1:a: =>6x+2=4x+12=>2x=10=>x=5b: =>(x-1)(x+1+3)=0=>(x-1)(x+4)=0=>x=1 hoặc x=-4c: ĐKXĐ: x<>3; x<>-3PT =>\(\left(x+1\right)\left(x+3\right)-\left(x-2\right)\left(x-3\right)=2x+4\)=>x^2+4x+3-x^2+5x-6=2x+4=>9x-3=2x+4=>x=1(nhận)Câu trả lời: Câu 1:a: =>6x+2=4x+12=>2x=10=>x=5b: =>(x-1)(x+1+3)=0=>(x-1)(x+4)=0=>x=1 hoặc x=-4c: ĐKXĐ: x<>3; x<>-3PT =>\(\left(x+1\right)\left(x+3\right)-\left(x-2\right)\left(x-3\right)=2x+4\)=>x^2+4x+3-x^2+5x-6=2x+4=>9x-3=2x+4=>x=1(nhận)