\(=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}=3^{28}-3^{27}-3^{26}=\)
\(=3^{26}\left(3^2-3-1\right)=3^{26}.5⋮5\)
Đặt A = 81⁷ - 27⁹ - 9¹³
= (3⁴)⁷ - (3³)⁹ - (3²)¹³
= 3²⁸ - 3²⁷ - 3²⁶
= 3²⁵.(3³ - 3² - 3)
= 3²⁵.(27 - 9 - 3)
= 3²⁵.15 ⋮ 15
Vậy A ⋮ 15