\(x=\left(\sqrt{5}-\sqrt{3}\right)\cdot\sqrt{8+2\sqrt{15}}\)
\(=\left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}+\sqrt{3}\right)=5-3=2\)
Thay x=2 vào M, ta được:
\(M=\dfrac{\sqrt{4\cdot2+4+\dfrac{1}{2}}}{\sqrt{2}\cdot\left|2\cdot2^2-2-1\right|}=\dfrac{5\sqrt{2}}{2}:5\sqrt{2}=\dfrac{1}{2}\)
\(M=\dfrac{\sqrt{\left(\sqrt{4x}+\sqrt{\dfrac{1}{x}}\right)^2}}{\sqrt{x}.2x^2-x-1}=\dfrac{\sqrt{4x}+\sqrt{\dfrac{1}{x}}}{2x-x-1}\)
\(M=\dfrac{\sqrt{4x}+\sqrt{\dfrac{1}{x}}}{x-1}\)
thay x = ..... ( trên đề )