\(d\left(M;\left(ABCD\right)\right)=\dfrac{1}{2}d\left(S;\left(ABCD\right)\right)=\dfrac{a}{2}\)
Đúng 0
Bình luận (1)
Theo định lý Talet ta luôn có:
\(\dfrac{MK}{SH}=\dfrac{AM}{SA}=\dfrac{1}{2}\Rightarrow MK=\dfrac{1}{2}SH\)
Hay \(d\left(M;\left(ABCD\right)\right)=\dfrac{1}{2}d\left(S;\left(ABCD\right)\right)\)
Đúng 0
Bình luận (0)