Câu 1: B
Câu 2: C
Câu 3:
\(Q=b^{\dfrac{5}{3}}\cdot\sqrt[3]{b}=b^{\dfrac{5}{3}}\cdot b^{\dfrac{1}{3}}=b^{\dfrac{5}{9}}\)
=>Chọn C
Câu 4:
\(a^{\dfrac{3}{2018}}\cdot\sqrt[2018]{a}=a^{\dfrac{3}{2018}}\cdot a^{\dfrac{1}{2018}}=a^{\dfrac{3}{2018^2}}\)
=>CHọn D
Câu 5: \(\sqrt[4]{a^{\dfrac{2}{3}}}=a^{\dfrac{2}{3}\cdot\dfrac{1}{4}}=a^{\dfrac{2}{12}}=a^{\dfrac{1}{6}}=\sqrt[6]{a}\)
=>Chọn D
Câu 7: \(\left(a-2\right)^{\dfrac{1}{4}}< \left(a-2\right)^{\dfrac{1}{3}}\)
=>a-2>1
=>a>3
=>Chọn D
Câu 8: B
Câu 9:
\(P=\sqrt[3]{x^{ }\cdot\sqrt[4]{x^3\cdot\sqrt{x}}}\)
\(=\sqrt[3]{x\cdot\sqrt[4]{x^3\cdot x^{\dfrac{1}{2}}}}=\sqrt[3]{x\cdot\sqrt[4]{x^{\dfrac{7}{2}}}}\)
\(=\sqrt[3]{x\cdot x^{\dfrac{7}{2}\cdot\dfrac{1}{4}}}=\sqrt[3]{x\cdot x^{\dfrac{7}{8}}}=\sqrt[3]{x^{\dfrac{15}{8}}}=x^{\dfrac{15}{8}\cdot\dfrac{1}{3}}=x^{\dfrac{5}{8}}\)
=>Chọn C
Câu 10: B
