e) \(\sqrt{3+2\sqrt{2}}-5\sqrt{2}\)
= \(\sqrt{\sqrt{2}^2+2.1.\sqrt{2}+1^2}\) - 5\(\sqrt{2}\)
= \(\sqrt{\left(\sqrt{2}+1\right)^2}\) - 5\(\sqrt{2}\)
= \(\left|\sqrt{2}+1\right|\) - \(5\sqrt{2}\)
= 1 + \(\sqrt{2}-5\sqrt{2}\)
= 1 - \(4\sqrt{2}\)
Chúc bạn học tốt
e: Ta có: \(\sqrt{3+2\sqrt{2}}-5\sqrt{2}\)
\(=\sqrt{2}+1-5\sqrt{2}\)
\(=-4\sqrt{2}+1\)