Question

 giúp câu b:<

Answer 1

\(a,=\dfrac{x+2}{x+1}:\dfrac{x}{x+1}=\dfrac{x+2}{x}\\ b,=x^2-2x\cdot\dfrac{3x-x+2+x^2-2x}{x\left(x-2\right)}=x^2-\dfrac{2\left(x^2+2\right)}{x-2}\\ =\dfrac{x^3-2x^2-2x^2-2}{x-2}=\dfrac{x^3-4x^2-2}{x-2}\)