\(\Leftrightarrow\sqrt{3}x-3\sqrt{3}=4-3x\)
\(\Leftrightarrow\left(3+\sqrt{3}\right)x=4+3\sqrt{3}\)
\(\Leftrightarrow x=\dfrac{4+3\sqrt{3}}{3+\sqrt{3}}=\dfrac{3+5\sqrt{3}}{6}\)
Giai phuong trinh : \(\left(x+5\right)\sqrt{\left(x+1\right)+1}=\sqrt[3]{\left(3x+4\right)}\)
Giai phuong trinh:
\(28+\sqrt[3]{x^2}=3x+2\sqrt[3]{x}+\left(x-4\right)\sqrt{x-7}\)
Giai phuong trinh giup minh 3 cau nay voi
a,\(3x\left(2-\sqrt{4}\right)=3\left(\sqrt{4}x+1\right)\)
b,\(\left(5-x\right).\left(\sqrt{3}+x\right)-5=0.\)
c,\(\left(x^2-2x\right)+\left(-4+8x\right)=0.\)
giai pt sau
\(\sqrt{3x-1}-\sqrt{x+2}.\sqrt{3x^2+7x+2}+4=4x-2\)
\(x^2-5x+3.\sqrt{2x-1}=2.\sqrt{14-2x}+5\)
\(\left(x+1\right)\left(x+4\right)-3\sqrt{x^2+5x+2}=6\)
Giải phương trình, x>0
\(\frac{\left(x^3+3x^2\sqrt{x^3-3x+6}\right)\left(3x-x^3-2\right)}{2+\sqrt{x^3-3x+6}}=4\left[2\sqrt{\left(x^3-3x+6\right)^3}-\left(x^3-3x+6\right)^2\right]\)
Giải phương trình, x>0
\(\frac{\left(x^3+3x^2\sqrt{x^3-3x+6}\right)\left(3x-x^3-2\right)}{2+\sqrt{x^3-3x+6}}=4\left[2\sqrt{\left(x^3-3x+6\right)^3}-\left(x^3-3x+6\right)^2\right]\)
giải bất phương trình vô tỉ sau
\(\sqrt[4]{\left(x-3\right)\left(5-x\right)}+\sqrt[4]{x-3}+\sqrt[4]{5-x}+6\left(x-1\right)\sqrt{3\left(x-1\right)}< =x^3-3x^2+3x+29\)
\(\left(5\right)\sqrt{x+3-4\sqrt{x-1}}\sqrt{x+8+6\sqrt{x-1}}=5\)
\(\left(6\right)2x^2+3x+\sqrt{2x^2+3x+9}=33\)
\(\left(7\right)\sqrt{3x^2+6x+12}+\sqrt{5x^4-10x^2+30}=8\)
\(\left(8\right)x+y+z+8=2\sqrt{x-1}+4\sqrt{y-2}+6\sqrt{z-3}\)
Giai phương trình \(\sqrt{3x^2-6x-6}=3\sqrt{\left(2-x\right)^5}+\left(7x-19\right)\sqrt{2-x}\)cảm ơn các bạn đã giải hộ mình .
\(B=\sqrt[3]{\frac{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4}}{2}}+\sqrt[3]{\frac{x^3-3x-\left(x^2-1\right)\sqrt{x^2-4}}{2}}\\ vs\\ x=\sqrt[3]{2015}\)