Question

Giải Pt \(\dfrac{14}{20-6x-2x^2}+\dfrac{x^2+4x}{x^2+5x}-\dfrac{x+3}{2-x}+3=0\)

Answer 1

\(\Leftrightarrow\dfrac{-7}{x^2+3x-10}+\dfrac{x+4}{x+5}+\dfrac{x+3}{x-2}+3=0\)

\(\Leftrightarrow-7+x^2+2x-8+x^2+8x+15+3x^2+9x-30=0\)

\(\Leftrightarrow5x^2+19x-30=0\)

hay \(x\in\left\{\dfrac{6}{5}\right\}\)