Question

Giải phương trình:
\(\dfrac{x-2}{6}\)+\(\dfrac{2x-1}{2}\)=\(\dfrac{x-1}{3}\)

Answer 1

 

\(\dfrac{\left(x-2\right)}{6}\)+\(\dfrac{\left(2x-1\right).3}{6}\)=\(\dfrac{\left(x-1\right).2}{6}\)
=> x-2+6x-3 = 2x-2
<=> x+6x-2x = -2+2+3
<=> 5x = 3
<=> x = 3/5

Answer 2

\(\dfrac{x-2}{6}\) +\(\dfrac{2x-1}{2}\) = \(\dfrac{x-1}{3}\)

<=>x-2+3(2x-1)=2(x-1)

<=>x-2+6x-3=2x-2

<=>7x-5=2x-2

<=>5x=3

<=>x=\(\dfrac{3}{5}\)