Question

giải phương trình

x-\(\dfrac{5x+2}{6}\)=\(\dfrac{7-3x}{4}\)

Answer 1

\(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\)

\(\Leftrightarrow\dfrac{12x-2\left(5x+2\right)}{12}=\dfrac{3\left(7-3x\right)}{12}\)

\(\Leftrightarrow\dfrac{12x-10x-4}{12}=\dfrac{21-9x}{12}\)

\(\Leftrightarrow12x-10x-4=21-9x\)

\(\Leftrightarrow12x-10x+9x=21+4\)

\(\Leftrightarrow11x=25\)

\(\Leftrightarrow x=\dfrac{25}{11}\)

Vậy phương trình có nghiệm duy nhất \(x=\dfrac{25}{11}\)

Answer 2

Answer 3

\(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\)

\(\Leftrightarrow\dfrac{12x}{12}-\dfrac{2\left(5x+2\right)}{12}=\dfrac{3\left(7-3x\right)}{12}\)

\(\Leftrightarrow12x-10x-4=21-9x\)

\(\Leftrightarrow12x-10x+9x=4+21\)

\(\Leftrightarrow11x=25\)

\(\Leftrightarrow x=\dfrac{25}{11}\)

Tập nghiệm của phương trình S = \(\left\{\dfrac{25}{11}\right\}.\)