Question

Giải phương trình sau:

(x² - 2) - (x - 2)(3x - 7) = 0

Answer 1

\(\left(x^2-2\right)-\left(x-2\right)\left(3x-7\right)=0\\ \Leftrightarrow x^2-2-\left(3x^2-6x-7x+14\right)=0\\ \Leftrightarrow x^2-2-3x^2+13x-14=0\\ \Leftrightarrow-2x^2+13x-16=0\\\Leftrightarrow \left[{}\begin{matrix}x=\dfrac{13+\sqrt{41}}{4}\\x=\dfrac{13-\sqrt{41}}{4}\end{matrix}\right.\)

Answer 2

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