Bài 3: Phương trình đưa được về dạng ax + b = 0
Các câu hỏi tương tự
Giải các phương trình sau :
a) dfrac{5left(x-1right)+2}{6}-dfrac{7x-1}{4}dfrac{2left(2x+1right)}{7}-5
b) dfrac{3left(x-3right)}{4}+dfrac{4x-10,5}{10}dfrac{3left(x+1right)}{5}+6
c) dfrac{2left(3x+1right)+1}{4}-5dfrac{2left(3x-1right)}{5}-dfrac{3x+2}{10}
d) dfrac{x+1}{3}+dfrac{3left(2x+1right)}{4}dfrac{2x+3left(x+1right)}{6}+dfrac{7+12x}{12}
Đọc tiếp
Giải các phương trình sau :
a) \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
b) \(\dfrac{3\left(x-3\right)}{4}+\dfrac{4x-10,5}{10}=\dfrac{3\left(x+1\right)}{5}+6\)
c) \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
d) \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\)
Giải pt sau:
a) \(\left(\dfrac{8}{1.9}+\dfrac{8}{9.17}+\dfrac{8}{17.25}+....+\dfrac{8}{49.57}\right)+2.\left(x-1\right)=\dfrac{2x+7}{3}+\dfrac{5x-8}{4}\)
b) \(\left(x+2\right).\left(x-2\right).\left(x^2-10\right)=72\)
c) (x+3)4+ (x+5)4 = 2
Giải các phương trình sau :
a) \(\dfrac{2x}{3}+\dfrac{2x-1}{6}=4-\dfrac{x}{3}\)
b) \(\dfrac{x-1}{2}+\dfrac{x-1}{4}=1-\dfrac{2\left(x-1\right)}{3}\)
c) \(\dfrac{2-x}{2001}-1=\dfrac{1-x}{2002}-\dfrac{x}{2003}\)
Giải các phương trình sau:
a, \(\dfrac{3\left(5x-2\right)}{4}-2=\dfrac{7x}{3}-5\left(x-7\right)\)
b, \(\dfrac{x+5}{2}+\dfrac{3-2x}{4}=x-\dfrac{7+x}{6}\)
c, \(\dfrac{x-3}{11}+\dfrac{x+1}{3}=\dfrac{x+7}{9}-1\)
d, \(\dfrac{3x-0,4}{2}+\dfrac{1,5-2x}{3}=\dfrac{x+0,5}{5}\)
giải phương trình ;
\(\dfrac{\left(7x+1\right).\left(x-2\right)}{10}+\dfrac{2}{5}=\dfrac{\left(x-2\right)^2}{5}+\dfrac{\left(x-1\right).\left(x-3\right)}{2}\)
SN
25 tháng 1 2022 lúc 14:01
1,dfrac{5left(x-1right)+2}{6}-dfrac{7x-1}{4x}dfrac{2left(2x+1right)}{7}-52,dfrac{3left(x-3right)}{4}+dfrac{4x-10,5}{10}dfrac{3
left(x+1right)}{5}+63,dfrac{2left(3x+1right)+1}{4}-5dfrac{2left(3x-1right)}{5}-dfrac{3x+2}{10}Diễn giải ra cho em với ạ!Em cảm ơn
Đọc tiếp
1,\(\dfrac{5\left(x-1\right)+2}{6}\)-\(\dfrac{7x-1}{4x}\)=\(\dfrac{2\left(2x+1\right)}{7}\)-5
2,\(\dfrac{3\left(x-3\right)}{4}\)+\(\dfrac{4x-10,5}{10}\)=\(\dfrac{3 \left(x+1\right)}{5}\)+6
3,\(\dfrac{2\left(3x+1\right)+1}{4}\)-5=\(\dfrac{2\left(3x-1\right)}{5}\)-\(\dfrac{3x+2}{10}\)
Diễn giải ra cho em với ạ!Em cảm ơn
a) \(\dfrac{x-3}{5}=6-\dfrac{1-2x}{3}\)
b) \(\dfrac{3x-2}{6}-5=\dfrac{3-2\left(x+7\right)}{4}\)
c) \(2\left(x+\dfrac{3}{5}\right)=5-\left(\dfrac{13}{5}+x\right)\)
d) \(\dfrac{7x}{8}-5\left(x-9\right)=\dfrac{20x+1,5}{6}\)
SN
25 tháng 1 2022 lúc 20:31
4,dfrac{x+1}{3}+dfrac{3left(2x+1right)}{4}dfrac{2x+3left(x+1right)}{6}+dfrac{7+12x}{12}5,dfrac{2x}{3}+dfrac{2x-1}{6}4-dfrac{x}{3}6,dfrac{x-1}{2}+dfrac{x-1}{4}1-dfrac{2left(x-1right)}{3}
Đọc tiếp
4,\(\dfrac{x+1}{3}\)+\(\dfrac{3\left(2x+1\right)}{4}\)=\(\dfrac{2x+3\left(x+1\right)}{6}\)+\(\dfrac{7+12x}{12}\)
5,\(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\)=4-\(\dfrac{x}{3}\)
6,\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)=1-\(\dfrac{2\left(x-1\right)}{3}\)
tìm n của phương trình \(x^2-\dfrac{2n-2x}{4}-2x+5n=x^3-9x^2+10\)
có nghiệm bằng \(\dfrac{1}{3}\)của phương trình \(\left(x+1\right)\left(x+3\right)=x\left(x-3\right)+24\)