Question

giải phương trình sau:

\(\dfrac{x-5}{95}+\dfrac{x-132}{32}=\dfrac{x-132}{31}+\dfrac{x-10}{90}\)

Answer 1

\(\Leftrightarrow\dfrac{x-5}{95}-1+\dfrac{x-132}{32}+1=\dfrac{x-131}{31}+1+\dfrac{x-10}{90}-1\)

=>x-100=0

hay x=100