=>\(\dfrac{3x^3-9x^2+9x-2x^3+2x^2-6x}{\left(x^2-3x+3\right)\left(x^2-x+3\right)}=-1\)
=>x^3-7x^2+3x=-[(x^2+3)^2-4x(x^2+3)+3x^2]
=>x^3-7x^2+3x+(x^2+3)^2-4x(x^2+3)+3x^2=0
=>x^3-4x^2+3x+x^4+6x^2+9-4x^3-12x=0
=>x^4-3x^3+2x^2-9x+9=0
=>(x-3)(x-1)(x^2+x+3)=0
=>x=3;x=1