\(log_2\left(5^{x+1}-25^x\right)=2\) \(\Leftrightarrow5^{x+1}-25^x=2^2\)\(\Leftrightarrow-\left(5^x\right)^2+5.5^x-4=0\).
Đặt \(5^x=t\left(t>0\right)\), phuyowng trình trở thành:
\(-t^2+5t-4=0\) \(\Leftrightarrow\left[{}\begin{matrix}t=1\\t=4\end{matrix}\right.\).
\(t=1\Leftrightarrow5^x=1\) \(\Leftrightarrow x=0\).
\(t=4\Leftrightarrow5^x=4\Leftrightarrow x=log_54\).