|5x-4|=|x+1|
⇔ 5x-4=x+1 ⇔ 4x=-5 ⇔ x=\(\dfrac{-5}{4}\)
5x-4=-x+1 6x=-3 x=\(\dfrac{-1}{2}\)
Vậy nghiệm của phương trình là x=\(\dfrac{-5}{4}\);x=\(\dfrac{-1}{2}\)
Ta có: \(\left|5x-4\right|=\left|x+1\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}5x-4=x+1\\5x-4=-x-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}5x-x=1+4\\5x+x=-1+4\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}4x=5\\6x=3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{1}{2}\end{matrix}\right.\)
Vậy: \(S=\left\{\dfrac{5}{4};\dfrac{1}{2}\right\}\)