a: \(\dfrac{12}{7}\cdot\dfrac{3}{4}:\dfrac{3}{14}=\dfrac{36}{28}\cdot\dfrac{14}{3}=\dfrac{9}{7}\cdot\dfrac{14}{3}=\dfrac{9}{3}\cdot\dfrac{14}{7}=3\cdot2=6\)
b: 2+5/2:18
=2+5/36
=72/36+5/36
=77/36
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\(\dfrac{12}{7}\times\dfrac{3}{4}:\dfrac{3}{14}\)
\(=\dfrac{12}{7}\times\dfrac{3}{4}\times\dfrac{14}{3}\)
\(=\dfrac{12\times3\times14}{7\times4\times3}\)
\(=\dfrac{3\times4\times7\times2\times3}{3\times4\times7}\)
\(=2\times3\)
\(=6\)
\(2+\dfrac{5}{2}:18\)
\(=2+\dfrac{5}{2}\times\dfrac{1}{18}\)
\(=2+\dfrac{5}{36}\)
\(=\dfrac{72}{36}+\dfrac{5}{36}\)
\(=\dfrac{77}{36}\)
#Toru
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