Ta có: \(x^3-8-\left(x-2\right)\left(x-12\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x^2+2x+4-x+12\right)=0\)
\(\Leftrightarrow x-2=0\)
hay x=2
Đúng 1
Bình luận (0)