\(\Leftrightarrow\left\{{}\begin{matrix}\left(x^2+2x\right)\left(2x+y\right)=9\\x^2+2x+2x+y=6\end{matrix}\right.\)
Đặt \(\left\{{}\begin{matrix}x^2+2x=a\\2x+y=b\end{matrix}\right.\) ta được:
\(\left\{{}\begin{matrix}ab=9\\a+b=6\end{matrix}\right.\) theo Viet đảo, a và b là nghiệm của:
\(t^2-6t+9=0\Rightarrow t=3\Rightarrow a=b=3\)
\(\Rightarrow\left\{{}\begin{matrix}x^2+2x=3\\2x+y=3\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x^2+2x-3=0\\y=3-2x\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=1\\y=1\end{matrix}\right.\\\left\{{}\begin{matrix}x=3\\y=-3\end{matrix}\right.\end{matrix}\right.\)