Giải hệ phương trình : \(\left\{{}\begin{matrix}x-\frac{3}{4}y=0\\\frac{1}{2}\left(x+3\right)\left(y-3\right)=\frac{1}{2}xy+12\end{matrix}\right.\)
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Giải hệ phương trình : \(\left\{{}\begin{matrix}x=\frac{3}{4}y\\\frac{1}{2}\left(x+3\right)\left(x-3\right)=\frac{1}{2}xy+12\end{matrix}\right.\)
các bạn ơi !! giúp mình với đi
giải hệ
a) \(\left\{{}\begin{matrix}x^2+y^2=2xy+1\\x^3-y^3=2xy+3\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}x^2+\frac{4}{y^2}=4\\x-\frac{2}{y}-\frac{4x}{y}=-2\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}2y^2-x^2=1\\2x^3-y^3=2y-x\end{matrix}\right.\)
d) \(\left\{{}\begin{matrix}x^2+6y=6x\\y^2+9=2xy\end{matrix}\right.\)
Giải hệ phương trình
a. \(\left\{{}\begin{matrix}\dfrac{1}{2}\left(x+2\right)\left(y+3\right)-\dfrac{1}{2}xy=50\\\dfrac{1}{2}xy-\dfrac{1}{2}\left(x-2\right)\left(y-2\right)=32\end{matrix}\right.\)
b. \(\left\{{}\begin{matrix}\dfrac{3x+5}{x+1}-\dfrac{2}{y+4}=4\\\dfrac{2x}{x+1}-\dfrac{5y+9}{y+4}=9\end{matrix}\right.\)
c. \(\left\{{}\begin{matrix}x^2+y^2-2x-2y-23=0\\x-3y-3=0\end{matrix}\right.\)
d.\(\left\{{}\begin{matrix}\left(x-y\right)^2-3x-3y=4\\2x+y=3\end{matrix}\right.\)
Giải các hệ Pt sau:
a,\(\left\{{}\begin{matrix}-0,5x+1,2y=2,7\\x-4,5y=-7,5\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}5x+3y=19\\2x+9y=31\end{matrix}\right.\)
c,\(\left\{{}\begin{matrix}\frac{3}{4}x+\frac{2}{5}y=2,3\\x-\frac{3}{5}y=0,8\end{matrix}\right.\)
d,\(\left\{{}\begin{matrix}5\left(x+2y\right)-3\left(x-y\right)=99\\x-3y=7x-4y-17\end{matrix}\right.\)
Giải hệ phương trình \(\left\{{}\begin{matrix}\frac{1}{x}+\frac{1}{y}=\frac{3}{4}\\\frac{1}{2}\left(x+y\right)=3\end{matrix}\right.\)
Các bạn ơi !! giúp mình với đi !!!
giải hệ phương trình \(\left\{{}\begin{matrix}\frac{7}{x-y+2}-\frac{8}{x+y-1}=\frac{9}{2}\\\frac{3}{x-y+2}+\frac{2}{x+y-1}=4\end{matrix}\right.\)
Giải HPT:
a, \(\left\{{}\begin{matrix}x-y=-1\\\frac{2}{x}+\frac{3}{y}=2\end{matrix}\right.\)
b, \(\left\{{}\begin{matrix}x-\frac{2}{y}=1\\5x+\frac{4}{y}=9\end{matrix}\right.\)
Giải hệ pt sau :
\(\left\{{}\begin{matrix}\left(x-10\right)\left(y+\frac{4}{5}\right)=xy\\\left(x-20\right)\left(y+2\right)=xy\end{matrix}\right.\)
