2: Ta có: \(5^{x-1}=5^2\)nên x-1=2hay x=35: Ta có: \(2^{2x-1}=2^{11}\)nên 2x-1=11\(\Leftrightarrow2x=12\)hay x=68: Ta có: \(5^{2x-4}=5^{10}\)\(\Leftrightarrow2x-4=10\)\(\Leftrightarrow2x=14\)hay x=7Câu trả lời: 2: Ta có: \(5^{x-1}=5^2\)nên x-1=2hay x=35: Ta có: \(2^{2x-1}=2^{11}\)nên 2x-1=11\(\Leftrightarrow2x=12\)hay x=68: Ta có: \(5^{2x-4}=5^{10}\)\(\Leftrightarrow2x-4=10\)\(\Leftrightarrow2x=14\)hay x=7