\(\sqrt{9x^2-6x+1}=7\left(x\in R\right)\)
\(\Leftrightarrow\sqrt{\left(3x-1\right)^2}=7\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-1=7\\3x-1=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-2\end{matrix}\right.\)
Vậy : \(S=\left\{-2;\dfrac{8}{3}\right\}\)
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