Question

Giải bất phương trình: \(\dfrac{-X^2-3x+18}{\left(x-2\right)\left(x+2\right)}< 0 \\ \\ \\ B\text{ài}v\text{ề}D\text{ấu}nh\text{ị}th\text{ức}b\text{ậc}nh\text{ất}\)

Answer 1

\(\dfrac{-x^2-3x+18}{\left(x-2\right)\left(x+2\right)}< 0\)

\(\Leftrightarrow\dfrac{x^2+3x-18}{\left(x-2\right)\left(x+2\right)}>0\)

 

Theo BXD, ta có: f(x)>0

=>\(x\in\left(-\infty;-6\right)\cup\left(-2;2\right)\cup\left(3;+\infty\right)\)