Question

Giải bất phương trình

a; 2x-3>5

b; \(\dfrac{x-1}{2}\)-1 \(\le\) \(\dfrac{2\left(x+1\right)}{3}\)

Answer 1

a, 2x-3>5

<=> 2x>5+3

<=> 2x>8

<=> x>4

Vậy S={x|x>4}

Answer 2

a) \(2x-3>5\)

\(\Leftrightarrow2x>8\)

\(\Leftrightarrow x>4\)

Tập nghiệm: \(S=\left\{x|x>4\right\}\)

b) \(\dfrac{x-1}{2}-1\le\dfrac{2\left(x+1\right)}{3}\)

\(\Leftrightarrow\dfrac{3\left(x-1\right)}{6}-\dfrac{6}{6}\le\dfrac{4\left(x+1\right)}{6}\)

\(\Leftrightarrow3x-3-6\le4x+4\)

\(\Leftrightarrow-x\le13\)

\(\Leftrightarrow x\ge-13\)

Tập nghiệm: \(S=\left\{x|x\ge-13\right\}\)