a: \(=\dfrac{2}{3}-\dfrac{4}{15}+\dfrac{1}{5}=\dfrac{10}{15}-\dfrac{4}{15}+\dfrac{3}{15}=\dfrac{9}{15}=\dfrac{3}{5}\)
b: \(=\dfrac{2^{27}\cdot3^{16}}{2^{16}\cdot3^{16}}=2\)
c: =11+2010=2021
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a, \(=\dfrac{2}{3}-\dfrac{4}{15}+\dfrac{1}{5}=\dfrac{3}{5}\)
b, \(\dfrac{8^9.9^8}{6^{16}}=\dfrac{2^{27}.3^{16}}{2^{16}.3^{16}}=2^{11}\)
c, = 11 + 2010 = 2021
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