Bài 3:
1: \(\Leftrightarrow2x^2+4x-x-2-2x^2-2x=0\)
=>x-2=0
hay x=2
2: \(\Leftrightarrow x^2-4-x^2-x=3\)
=>-x=7
hay x=-7
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Bài 3.
`1)`\(\left(2x-1\right)\left(x+2\right)-2x\left(x+1\right)=0\)
`<=>2x^2+4x-x-2-2x^2-2x=0`
`<=>x-2=0`
`<=>x=2`
Vậy `x=2`
`2)`\(\left(x-2\right)\left(x+2\right)-x\left(x+1\right)=3\)
`<=>x^2-4-x^2-x=3`
`<=>-x=7`
`<=>x=-7`
Vậy `x=-7`
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