`6 : 3/4 : 3/4 = 6 xx 4/3 : 3/4 = 24/3 : 3/4 = 8 : 3/4 = 8 xx 4/3 = 32/3`
`=>S`
`6 : 3/4 : 3/4 = 6 xx 4/3 : 3/4 = 24/3 : 3/4 = 8 : 3/4 = 8 xx 4/3 = 32/3`
`=> Đ`
Đúng ghi Đ sai ghi S
\(\dfrac{1}{4}\) = \(\dfrac{25}{100}\) ❏
\(\dfrac{3}{8}=\dfrac{35}{100}\) ❏
\(\dfrac{3}{8}=\dfrac{375}{1000}\) ❏
Bài 6. Đúng ghi Đ sai ghi S vào ô trống:
a, \(\dfrac{7}{9}\)\(>\dfrac{7}{8}\) b, \(\dfrac{3}{5}\)\(< \dfrac{5}{7}\) c, \(\dfrac{111}{112}\)\(=\dfrac{112}{113}\)\(\) d, \(\dfrac{13}{9}\)\(=\dfrac{117}{81}\)
a \(\dfrac{3}{4}+\dfrac{5}{6}\)=
b\(\dfrac{1}{2}+\dfrac{7}{12}\)=
c\(\dfrac{2}{3}\)x\(\dfrac{3}{4}\)=
d\(\dfrac{7}{4}:2\)=
ghi chi tiết giúp mình với ạ.Cảm ơn mọi người!
Đúng ghi Đ ,sai ghi S
a) 705\(dm^2\)>75\(m^2\) b) 97.000\(m^2\)<10 \(hm^2\) giúp mik với mik cần gấp
c) \(\dfrac{3}{4}\) \(km^2\)= 7.500 \(dam^2\) d) 6\(m^2\) 34 \(dm^2\)> \(6\dfrac{41}{100}\)\(m^2\)
Đúng ghi Đ ,sai ghi S
a) 705\(dm^2\)>75\(m^2\) ... b) 97.000\(m^2\)<10 \(hm^2\) ... giúp mik với mik cần gấp
c) \(\dfrac{3}{4}\) \(km^2\)= 7.500 \(dam^2\) ... d) 6\(m^2\) 34 \(dm^2\)> \(6\dfrac{41}{100}\)\(m^2\) ..
a)\(\dfrac{7}{8}\)x\(\dfrac{3}{13}\)+\(\dfrac{4}{9}\)x\(\dfrac{4}{13}\)
b)\(\dfrac{6}{5}\)+\(\dfrac{7}{3}\)+\(\dfrac{8}{9}\)
c)23: \(\dfrac{5}{14}\)+\(\dfrac{6}{7}\)+\(\dfrac{4}{9}\)
d)\(4\dfrac{1}{4}\)+\(7\dfrac{3}{7}\)-\(2\dfrac{4}{17}\)
e)8-(9\(\dfrac{2}{11}\)+\(\dfrac{8}{33}\))
Tìm a
a) \(2\dfrac{3}{4}-a+\dfrac{1}{4}=1\dfrac{1}{2}\)
b)3\(\dfrac{1}{4}-a-1\dfrac{3}{4}=\dfrac{7}{8}\)
c) 2\(\dfrac{5}{6}-1\dfrac{1}{2}-a=\dfrac{1}{6}\)
\(\dfrac{1}{3}+\dfrac{2}{3}=\)
\(\dfrac{4}{5}+\dfrac{5}{6}=\)
\(\dfrac{4}{5}-\dfrac{3}{5}=\)
\(\dfrac{9}{8}-\dfrac{4}{2}=\)
\(\dfrac{8}{5}x\dfrac{5}{8}=\)
\(\dfrac{6}{7}x\dfrac{4}{7}=\)
\(\dfrac{4}{5}:\dfrac{4}{5}=\)
\(\dfrac{5}{5}:\dfrac{5}{5}=\)
a,
Tính
a)5 \(\dfrac{3}{8}\)+ 1 \(\dfrac{1}{4}\)+ 3\(\dfrac{6}{7}\)
b) 2\(\dfrac{3}{8}\)- 1\(\dfrac{1}{4}\)+ 5 \(\dfrac{1}{3}\)
Tính A= \(\dfrac{1}{2}\)- \(\dfrac{2}{3}\)+\(\dfrac{3}{4}\)-\(\dfrac{4}{5}\)+\(\dfrac{5}{6}\)-\(\dfrac{6}{7}\)-\(\dfrac{6}{5}\)+\(\dfrac{4}{5}\)-\(\dfrac{3}{4}\)+\(\dfrac{2}{3}\)-\(\dfrac{1}{2}\)
