Ta có:
\(n_{O2}=0,5\left(mol\right)\)
\(PTHH:CH_4+2O_2\rightarrow CO_2+2H_2O\)
\(\Rightarrow n_{CH4}=\frac{1}{2}n_{O2}=0,25\left(mol\right)\)
Hỗn hợp sau gồm:N2 và CO2
\(n_{hh}=\frac{22,4}{22,4}=1\left(mol\right)\)
\(n_{N2}+n_{CO2}=1\left(mol\right)\Rightarrow n_{N2}=0,75\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}\%V_{CH4}=\frac{0,25}{0,25+0,75}.100\%=25\%\\\%V_{N2}=100\%-25\%=75\%\end{matrix}\right.\)
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