\(\dfrac{x+1}{3}=\dfrac{1-3x}{-5}\)
=>\(-5\left(x+1\right)=3\left(1-3x\right)\)
=>\(5\left(x+1\right)=3\left(3x-1\right)\)
=>5x+5=9x-3
=>5x-9x=-3-5
=>-4x=-8
=>x=2
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