ĐKXĐ: x<>2
\(\dfrac{x-2}{16}=\dfrac{-4}{2-x}\)
=>\(\dfrac{x-2}{16}=\dfrac{4}{x-2}\)
=>\(\left(x-2\right)^2=4\cdot16=64\)
=>\(\left[{}\begin{matrix}x-2=8\\x-2=-8\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=10\left(nhận\right)\\x=-6\left(nhận\right)\end{matrix}\right.\)